The structure of a typical conic optimization problem is

$\begin{split}\begin{array}{lccccl} \mbox{minimize} & & & c^T x+c^f & & \\ \mbox{subject to} & l^c & \leq & A x & \leq & u^c, \\ & l^x & \leq & x & \leq & u^x, \\ & & & Fx+g & \in & \D, \end{array}\end{split}$

(see Sec. 12 (Problem Formulation and Solutions) for detailed formulations). Here we discuss how to set-up problems with the (rotated) quadratic cones.

MOSEK supports two types of quadratic cones, namely:

$\Q^n = \left\lbrace x \in \real^n: x_0 \geq \sqrt{\sum_{j=1}^{n-1} x_j^2} \right\rbrace.$

$\Qr^n = \left\lbrace x \in \real^n: 2 x_0 x_1 \geq \sum_{j=2}^{n-1} x_j^2,\quad x_0\geq 0,\quad x_1 \geq 0 \right\rbrace.$

For example, consider the following constraint:

$(x_4, x_0, x_2) \in \Q^3$

which describes a convex cone in $$\real^3$$ given by the inequality:

$x_4 \geq \sqrt{x_0^2 + x_2^2}.$

For other types of cones supported by MOSEK, see Sec. 14.8 (Supported domains) and the other tutorials in this chapter. Different cone types can appear together in one optimization problem.

## 7.2.1 Example CQO1¶

Consider the following conic quadratic problem which involves some linear constraints, a quadratic cone and a rotated quadratic cone.

(7.2)$\begin{split} \begin{array}{ll} \minimize & y_1 + y_2 + y_3 \\ \st & x_1 + x_2 + 2.0 x_3 = 1.0,\\ & x_1,x_2,x_3 \geq 0.0,\\ & (y_1,x_1,x_2) \in \Q^3,\\ & (y_2,y_3,x_3) \in \Qr^3. \end{array}\end{split}$

We start by creating the optimization model:

    Model M = new Model("cqo1");


We then define variables x and y. Two logical variables (aliases) z1 and z2 are introduced to model the quadratic cones. These are not new variables, but map onto parts of x and y for the sake of convenience.

      Variable x = M.variable("x", 3, Domain.greaterThan(0.0));
Variable y = M.variable("y", 3, Domain.unbounded());

// Create the aliases
//      z1 = [ y,x,x ]
//  and z2 = [ y,y,x ]
Variable z1 = Var.vstack(y.index(0),  x.slice(0, 2));
Variable z2 = Var.vstack(y.slice(1, 3), x.index(2));


The linear constraint is defined using the dot product:

      // Create the constraint
//      x + x + 2.0 x = 1.0
double[] aval = new double[] {1.0, 1.0, 2.0};
M.constraint("lc", Expr.dot(aval, x), Domain.equalsTo(1.0));


The conic constraints are defined using the logical views z1 and z2 created previously. Note that this is a basic way of defining conic constraints, and that in practice they would have more complicated structure.

      // Create the constraints
//      z1 belongs to C_3
//      z2 belongs to K_3
// where C_3 and K_3 are respectively the quadratic and
// rotated quadratic cone of size 3, i.e.
//                 z1 >= sqrt(z1^2 + z1^2)
//  and  2.0 z2 z2 >= z2^2
Constraint qc1 = M.constraint("qc1", z1, Domain.inQCone());
Constraint qc2 = M.constraint("qc2", z2, Domain.inRotatedQCone());


We only need the objective function:

      // Set the objective function to (y + y + y)
M.objective("obj", ObjectiveSense.Minimize, Expr.sum(y));


Calling the Model.solve method invokes the solver:

      M.writeTask("cqo1.task");
M.solve();


The primal and dual solution values can be retrieved using Variable.level, Constraint.level and Variable.dual, Constraint.dual, respectively:

      // Get the linear solution values
double[] solx = x.level();
double[] soly = y.level();

      // Get conic solution of qc1
double[] qc1lvl = qc1.level();
double[] qc1sn  = qc1.dual();

Listing 7.2 Fusion implementation of model (7.2). Click here to download.
package com.mosek.fusion.examples;
import mosek.fusion.*;

public class cqo1 {
public static void main(String[] args)
throws SolutionError {
Model M = new Model("cqo1");
try {
Variable x = M.variable("x", 3, Domain.greaterThan(0.0));
Variable y = M.variable("y", 3, Domain.unbounded());

// Create the aliases
//      z1 = [ y,x,x ]
//  and z2 = [ y,y,x ]
Variable z1 = Var.vstack(y.index(0),  x.slice(0, 2));
Variable z2 = Var.vstack(y.slice(1, 3), x.index(2));

// Create the constraint
//      x + x + 2.0 x = 1.0
double[] aval = new double[] {1.0, 1.0, 2.0};
M.constraint("lc", Expr.dot(aval, x), Domain.equalsTo(1.0));

// Create the constraints
//      z1 belongs to C_3
//      z2 belongs to K_3
// where C_3 and K_3 are respectively the quadratic and
// rotated quadratic cone of size 3, i.e.
//                 z1 >= sqrt(z1^2 + z1^2)
//  and  2.0 z2 z2 >= z2^2
Constraint qc1 = M.constraint("qc1", z1, Domain.inQCone());
Constraint qc2 = M.constraint("qc2", z2, Domain.inRotatedQCone());

// Set the objective function to (y + y + y)
M.objective("obj", ObjectiveSense.Minimize, Expr.sum(y));

// Solve the problem
M.solve();

// Get the linear solution values
double[] solx = x.level();
double[] soly = y.level();
System.out.printf("x1,x2,x3 = %e, %e, %e\n", solx, solx, solx);
System.out.printf("y1,y2,y3 = %e, %e, %e\n", soly, soly, soly);

// Get conic solution of qc1
double[] qc1lvl = qc1.level();
double[] qc1sn  = qc1.dual();

System.out.printf("qc1 levels = %e", qc1lvl);
for (int i = 1; i < qc1lvl.length; ++i)
System.out.printf(", %e", qc1lvl[i]);
System.out.print("\n");

System.out.printf("qc1 dual conic var levels = %e", qc1sn);
for (int i = 1; i < qc1sn.length; ++i)
System.out.printf(", %e", qc1sn[i]);
System.out.print("\n");

} finally {
M.dispose();
}
}
}